(-20xy^2+6)dx+(3y^2-20yx^2)dy=0

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Solution for (-20xy^2+6)dx+(3y^2-20yx^2)dy=0 equation:


Simplifying
(-20xy2 + 6) * dx + (3y2 + -20yx2) * dy = 0

Reorder the terms:
(6 + -20xy2) * dx + (3y2 + -20yx2) * dy = 0

Reorder the terms for easier multiplication:
dx(6 + -20xy2) + (3y2 + -20yx2) * dy = 0
(6 * dx + -20xy2 * dx) + (3y2 + -20yx2) * dy = 0
(6dx + -20dx2y2) + (3y2 + -20yx2) * dy = 0

Reorder the terms:
6dx + -20dx2y2 + (-20x2y + 3y2) * dy = 0

Reorder the terms for easier multiplication:
6dx + -20dx2y2 + dy(-20x2y + 3y2) = 0
6dx + -20dx2y2 + (-20x2y * dy + 3y2 * dy) = 0
6dx + -20dx2y2 + (-20dx2y2 + 3dy3) = 0

Combine like terms: -20dx2y2 + -20dx2y2 = -40dx2y2
6dx + -40dx2y2 + 3dy3 = 0

Solving
6dx + -40dx2y2 + 3dy3 = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Factor out the Greatest Common Factor (GCF), 'd'.
d(6x + -40x2y2 + 3y3) = 0

Subproblem 1

Set the factor 'd' equal to zero and attempt to solve: Simplifying d = 0 Solving d = 0 Move all terms containing d to the left, all other terms to the right. Simplifying d = 0

Subproblem 2

Set the factor '(6x + -40x2y2 + 3y3)' equal to zero and attempt to solve: Simplifying 6x + -40x2y2 + 3y3 = 0 Solving 6x + -40x2y2 + 3y3 = 0 Move all terms containing d to the left, all other terms to the right. Add '-6x' to each side of the equation. 6x + -40x2y2 + -6x + 3y3 = 0 + -6x Reorder the terms: 6x + -6x + -40x2y2 + 3y3 = 0 + -6x Combine like terms: 6x + -6x = 0 0 + -40x2y2 + 3y3 = 0 + -6x -40x2y2 + 3y3 = 0 + -6x Remove the zero: -40x2y2 + 3y3 = -6x Add '40x2y2' to each side of the equation. -40x2y2 + 40x2y2 + 3y3 = -6x + 40x2y2 Combine like terms: -40x2y2 + 40x2y2 = 0 0 + 3y3 = -6x + 40x2y2 3y3 = -6x + 40x2y2 Add '-3y3' to each side of the equation. 3y3 + -3y3 = -6x + 40x2y2 + -3y3 Combine like terms: 3y3 + -3y3 = 0 0 = -6x + 40x2y2 + -3y3 Simplifying 0 = -6x + 40x2y2 + -3y3 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Solution

d = {0}

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